Hi

Do not post HTML. Why you did not populate your list directly with coefficients 
by let say coef(lm.result)?

Anyway, you can reveal structure of individulal list component by 
str(your.object[[1]]). After that you can extract coefficient component and use 
sapply/lapply probably with rbind.

maybe

sapply(lapply(your.list, coef), rbind)

can do it.

Regards
Petr

> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of eliza botto
> Sent: Wednesday, September 11, 2013 4:23 PM
> To: r-help@r-project.org
> Subject: [R] list to matrix
> 
> Dear useRs,
> If i have a list of the following form and i want to convert the
> coefficient section of each element, combined into one matrix of
> dimension 3*5. How can i do that?I hope i am clear thank in advance
> 
> [[1]]
> Call:
> lm(formula = mm[, i] ~ 0 + (x0 + x + xx + y + yy))
> Coefficients:
>      x0        x       xx        y       yy
>  1.0000  -0.4250   0.2494   0.1683  -0.7449
> 
> [[2]]
> Call:
> lm(formula = mm[, i] ~ 0 + (x0 + x + xx + y + yy))
> Coefficients:
>      x0        x       xx        y       yy
>  1.0000  -0.6355   0.5876   0.2518  -0.7293
> 
> [[3]]
> Call:
> lm(formula = mm[, i] ~ 0 + (x0 + x + xx + y + yy))
> Coefficients:
>      x0        x       xx        y       yy
>  1.0000   0.5778   0.3838   0.4207  -0.1354
> 
>       [[alternative HTML version deleted]]
> 
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