I believe you want to use 'diff' and 'which' as in:
> diff(which(c(TRUE, 1:10 %in% c(3, 5, 6, 10) )))
[1] 3 2 1 4
Pat
On 17/09/2013 11:15, gildororo...@mail-on.us wrote:
I can do this:
1:10 %in% c(3, 5, 6, 10)
[1] FALSE FALSE TRUE FALSE TRUE TRUE FALSE FALSE FALSE TRUE
but what I wish to get is:
[1] 3 2 1 4
let me explain:
3 # [1:3] ends with TRUE, i.e. FALSE FALSE TRUE
2 # [4:5] ends with TRUE, i.e. FALSE TRUE
1 # [6:6] ends with TRUE, i.e. TRUE
4 # [7:10] ends with TRUE, i.e. FALSE FALSE FALSE TRUE
That is, %in% gave me a serial whether or not the element is in a set,
the length is equal to the former, i.e. 1:10
But I wish to get a serial of intevals of occurance of the element in
the set, the length is equal to the latter i.e. c(3, 5, 6, 10)
With ths task of finding the intervals, I found, with googling, a
function called findInterval. I did read every line of that manual, and
it seems to be for a completely different purpose.
Kindly help the poor newbie:)
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