Thanks, that seems to work.
On Fri, Nov 15, 2013 at 10:26 PM, arun kirshna [via R] <
ml-node+s789695n4680556...@n4.nabble.com> wrote:
> Hi,
>
> Try:
> var1 <- load("reshape_data.frame.RData")
> ##It is better not to name the objects with function names.
> dat1 <- data
> reshape1 <- reshape
> names(dat1)[grep("X\\d+",names(dat1))] <-
> gsub("[[:alpha:]]","X_",names(dat1)[grep("X\\d+",names(dat1))])
> res1 <- reshape(dat1,direction="long",varying=7:ncol(dat1),sep="_")
> res2 <- res1[with(res1,order(Yr,Seas,Flt.Svy,Gender,Part,NSAMP)),-9]
> row.names(res2) <- 1:nrow(res2)
> colnames(res2) <- colnames(reshape1)
> all.equal(res2,reshape1)
> #[1] TRUE
>
> A.K.
>
>
> Some advice on transforming my data would be appreciated. Attached is
> an .Rdata image with my examples (reshape_data.frame.Rdata). Within the
> image are 2 objects:
>
> 1) The "data" object contains an example of my original data
> format. The columns "X20" : "X50" are histogram bins, and the rows
> beneath are the number of observations (ie. counts) within those bins.
> The other columns; "Yr", "Seas", "Flt.Svy", "Gender", "Part", "NSAMP"
> are observation associated with each bin count.
>
> 2) The "reshape" object is the format I need to transform the "data"
> object into.
>
> I think the reshape() function is designed for this, and my
> "data" object is in wide format, and my "resphape" object would be in
> long format. If indeed reshape() is the best way to do this, I'm
> looking for help in calling the function to transform my data.
>
> Many thanks,
>
> Tim
>
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