On May 27, 2008, at 10:43 PM, Daniel Yang wrote:
Dear all,
I want to create a list that contains 0,1,2,3, ..., 10000 as its
elements. I used the following code, which apparently doesn't work
very well.
a <- 0
for(i in 1:10000) {
a <- list(a, i)
}
The result is not what I wanted. So how to create the bind lists
recursively so that the last element would be the newly added one
while the previous elements all remain the same?
Hm, for the particular problem you are asking, I think that:
as.list(0:10000)
should do the trick. I m guessing it might not work for the real
application you had in mind.
If you insist on the for loop, then you can do the following:
a <- list(0)
for(i in 1:10000) {
a <- c(a, i)
}
Though it's much smaller. In general, it is better to assign the
correct size to the list to begin with, I believe.
Thanks!
Daniel
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
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