On 07 Aug 2014, at 11:16 , jim holtman <[email protected]> wrote: > rle
...with a little tinkering, like > m <- c(1,cumsum(rle(a)$lengths)+1) > m [1] 1 4 6 12 16 18 23 34 then look at every 2nd element, discarding the last. -- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: [email protected] Priv: [email protected] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
