On 03/12/2014 7:37 AM, philippe massicotte wrote:
Hi everyone, I have a formula like this:

f <- as.formula(y ~ p0a * exp(-0.5 * ((x - p1a)/p2a)^2))

I would like to "dynamically" provide starting values for p0a, p1a, p2a. Is 
there a way to do it?

Just give a named vector of starting values.

#Params estimates
p <- c(12, 10, 1)

Should be p <- c(p0a = 12, p1a = 10, p2a = 1)

# This is where I have difficulties
mystart <- substitute(...)

nls(formula = f, start = mystart)

Now start = p will work. No need to mess with substitute. (And no need to use as.formula on the very first line; that's already a formula.)

Duncan Murdoch

Regards,
Philippe
                                        
        [[alternative HTML version deleted]]

______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to