Just to augment Bert’s comment, other options are likely to introduce some level of overhead that while perhaps looking better, will not be materially faster. Depending upon the length of your vector, you could do some testing to see.
One thing that might yield a little bit of performance improvement would be to pre-calculate the indices: set.seed(1) x <- rnorm(100) IND <- seq(20,100, by=20) > IND [1] 20 40 60 80 100 > x[IND] [1] 0.5939013 0.7631757 -0.1350546 -0.5895209 -0.4734006 x[IND] <- -x[IND] > x[IND] [1] -0.5939013 -0.7631757 0.1350546 0.5895209 0.4734006 But unless your vector is very large, I suspect the performance gain may be minimal in real time. Regards, Marc Schwartz > On Jun 18, 2015, at 3:07 PM, Bert Gunter <bgunter.4...@gmail.com> wrote: > > Your **is** the "coolest" and most efficient way to do this. It's > vectorized -- apply() stuff is not. > > Cheers, > Bert > > Bert Gunter > > "Data is not information. Information is not knowledge. And knowledge is > certainly not wisdom." > -- Clifford Stoll > > On Thu, Jun 18, 2015 at 12:40 PM, Frank S. <f_j_...@hotmail.com> wrote: > >> Hi everyone, >> >> I have an "x" vector and I would want to change the sign every 20 >> elements. For this puspose, >> I wrote the following code: >> >> set.seed(1) >> x <- rnorm(100) >> x >> x[seq(20,100, by=20)] <- -x[seq(20,100, by=20)] >> x >> >> However, I'm afraid it is a rudimentary form to get the desired result. >> II wonder wether there is a cool way to do so, that is, for example with >> apply or sign function. >> >> Thans in advanced for your help! >> >> Frank S. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
