Hi Yasil, If you look at what happens to a[,3] after the "strsplit" it is easy:
> a[,3] [1] "a,b" "c,d" Here a[,3] is two strings a$c <- strsplit(a$c, ",") > a[,3] [[1]] [1] "a" "b" [[2]] [1] "c" "d" Now a[,3] is a two element list. What R probably did was to take the first component of a[,3] to replace the existing two values. Now if you don't try to fool R: > a[,3]<-list(a[,3]) > a$c [[1]] [1] "a" "b" [[2]] [1] "c" "d" Jim On Wed, May 4, 2016 at 9:13 AM, Yasir Suhail <[email protected]> wrote: > Dear R developers and users, > > Consider the object : > >> a <- data.frame(a=c(1,2), b=c(2,3), c=c("a,b","c,d"), stringsAsFactors = F) >> a$c <- strsplit(a$c, ",") > > Re-assignment works fine for columns 1 and 2, but fails for column 3. If a > is a valid object, the assignment should work. > >> a[,1] <- a[,1] >> a[,2] <- a[,2] >> a[,3] <- a[,3] > Warning message: > In `[<-.data.frame`(`*tmp*`, , 3, value = list(c("a", "b"), c("c", : > provided 2 variables to replace 1 variables > > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
