Thank you!

> On Jun 20, 2016, at 12:41 PM, David L Carlson <[email protected]> wrote:
> 
> It does not test the first column, but a vector must have consecutive 
> indices. Since you did not assign a value, R inserts a missing value. If you 
> don't want to see it use
> 
>> results.pc.all[, -1]
>          [,1] [,2]
> results.2    1    2
> results.3    2    3
> 
> -------------------------------------
> David L Carlson
> Department of Anthropology
> Texas A&M University
> College Station, TX 77840-4352
> 
> -----Original Message-----
> From: R-help [mailto:[email protected]] On Behalf Of Brittany 
> Demmitt
> Sent: Monday, June 20, 2016 12:15 PM
> To: [email protected]
> Subject: [R] loop testing unidentified columns
> 
> Hello,
> 
> I want to compare all of the columns of one data frame to another to see if 
> any of the columns are equivalent to one another. The first column in both of 
> my data frames are the sample IDs and do not need to be compared. Below is an 
> example of the loop I am using to compare the two data frames that counts the 
> number of equivalent values there between two columns. So in this example the 
> value of 3 means that all three observations for the two columns being 
> compared were equivalent. The loop works fine but I do not understand why it 
> tests the first column of the sample IDs providing “NA” for the sum of 
> matching when my loop is specifying to only test columns 2-3.  
> 
> Thank you!
> 
> 
> #create dataframe A 
> A = matrix(c("a",3,4,"b",5,7,"c",3,7),nrow=3, ncol=3,byrow = TRUE)    
> A <- as.data.frame(A)
> A$V2 <- as.numeric(A$V2)
> A$V3 <- as.numeric(A$V3)
> str(A)
> 
> #create dataframe B
> B = matrix(c("a",1,1,"b",6,2,"c",2,2),nrow=3, ncol=3,byrow = TRUE)    
> B <- as.data.frame(B)
> B$V2 <- as.numeric(B$V2)
> B$V3 <- as.numeric(B$V3)
> str(B)
> 
> results.2 <- numeric()
> results.3  <- numeric()
> 
> 
> #compare columns to identify those that are identical in the two dataframes 
> for(i in 2:3){
>  results.2[i] <- sum(A[,2]==B[,i])
>  results.3[i] <- sum(A[,3]==B[,i])
>  results.pc.all <- rbind(results.2,results.3)
> }
> results.pc.all
> 
> ______________________________________________
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