Dear all, I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t like to divide the total copy numbers of methanogens ( on average 10^8) by bacteria (10^10) because they have different exponents and bases. So, my idea is to standardize both microorganisms counts to 10^3.
Hypothetical example of what I`d like to do: Total Methanogens: 28 x 10^3 Total bacteria: 710 x 10^3 Total: 710 + 28= 738 x 10^3 Met/bac Ratio : (28/738)*100 = 3.79% How could I perform this calculation in R? Thanks, -- Andre [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.