If your goal is to visualize the predicted curve from an lm fit (or
other model fit) then you may want to look at the Predict.Plot and
TkPredict functions from the TeachingDemos package.




On Sun, Sep 25, 2016 at 7:01 AM, Matti Viljamaa <mvilja...@kapsi.fi> wrote:
> I’m trying to plot regression lines using curve()
>
> The way I do it is:
>
> bs <- coef(fit2)
>
> and then for example:
>
> curve(bs["(Intercept)"]+bs["mies"]*0+bs["kouluB"]+bs["lka"]*x+bs["kouluB:clka"]*clka,
>  from=min(lka), to=max(lka), add=TRUE, col='red')
>
> This above code runs into error:
>
> Error in curve(bs["(Intercept)"] + bs["mies"] * 0 + bs["kouluB"] + bs["lka"] 
> *  :
>   'expr' did not evaluate to an object of length 'n'
> In addition: Warning message:
> In bs["(Intercept)"] + bs["mies"] * 0 + bs["kouluB"] + bs["lka"] *  :
>   longer object length is not a multiple of shorter object length
>
> Which I’ve investigated might be related to the lengths of the different 
> objects being multiplied or summed.
> Taking length(g$x) or length(g$y) of
>
> g <- curve(bs["(Intercept)"]+bs["mies"]*0+bs["kouluB"]+bs["lka"]*x, 
> from=min(lka), to=max(lka), add=TRUE, col='red')
>
> returns 101.
>
> However length(lka) is 375. But perhaps these being different is not the 
> problem?
>
> I however do see that the whole range of lka is not plotted, for some reason. 
> So how can I be sure
> that it passes through all x-values in lka? And i.e. that the lengths of 
> objects inside curve() are correct?
>
> What can I do?
> ______________________________________________
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-- 
Gregory (Greg) L. Snow Ph.D.
538...@gmail.com

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