> -----Original Message----- > testseq<-seq(1:20) > testchange<-ifelse(testseq<=4,'x',testseq) > testchange<-c(ifelse(testseq<=4,'x',testseq),ifelse(testseq>=5,'y',testseq)) > > The last instruction causes the vector 'testchange' to change dimensions,
Of course it does. ifelse(test, yes, no) returns a vector of length length(test). Your last line concatenates two of them, so you'll get a vector of length 40. You might also want to note that you are replacing numbers with character strings, so ifelse(testseq<=4,'x',testseq) will return four 'x's and then - because R has to coerce everything to a single type - character representations of numbers 5:20. That will not then respond well to subsequent numeric comparisons ... S Ellison ******************************************************************* This email and any attachments are confidential. Any use...{{dropped:8}} ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.