It’s not clear to me what your actual structure is. Can you provide
str(object)? Assuming it is a list, and you want the mean over all cells or
columns, you might want like this:
myData <- vector("list", 3)
for(i in 1:3){
myData[[i]] <- matrix(rnorm(100), 10, 10)
}
### mean over all cells
sapply(myData, function(x) mean(x))
### mean over all columns
sapply(myData, function(x) colMeans(x))
From: lily li [mailto:chocol...@gmail.com]
Sent: Tuesday, May 09, 2017 10:44 AM
To: Doran, Harold <hdo...@air.org>
Cc: R mailing list <r-help@r-project.org>
Subject: Re: [R] About calculating average values from several matrices
I'm trying to get a new dataframe or whatever to call, which has the same
structure with each file as listed above. For each cell in the new dataframe or
the new file, it is the average value from former dataframes at the same
location. Thanks.
On Tue, May 9, 2017 at 8:41 AM, Doran, Harold
<hdo...@air.org<mailto:hdo...@air.org>> wrote:
Are you trying to take the mean over all cells, or over rows/columns within
each dataframe. Also, are these different dataframes stored within a list or
are they standalone?
-----Original Message-----
From: R-help
[mailto:r-help-boun...@r-project.org<mailto:r-help-boun...@r-project.org>] On
Behalf Of lily li
Sent: Tuesday, May 09, 2017 10:39 AM
To: R mailing list <r-help@r-project.org<mailto:r-help@r-project.org>>
Subject: [R] About calculating average values from several matrices
Hi R users,
I have a question about manipulating the data.
For example, there are several such data frames or matrices, and I want to
calculate the average value from all the data frames or matrices. How to do it?
Also, should I convert them to data frame or matrix first? Right now, when I
use typeof() function, each one is a list.
file1
jan feb mar apr may jun jul aug sep oct nov
app1 1.1 1.2 0.8 0.9 1.3 1.5 2.2 3.2 3.0 1.2 1.1
app2 3.1 3.2 2.8 2.5 2.3 2.5 3.2 3.0 2.9 1.8 1.8
app3 5.1 5.2 3.8 4.9 5.3 5.5 5.2 4.2 5.0 4.2 4.1
file2
jan feb mar apr may jun jul aug sep oct nov
app1 1.9 1.5 0.5 0.9 1.2 1.8 2.5 3.7 3.2 1.5 1.6
app2 3.5 3.7 2.3 2.2 2.5 2.0 3.6 3.2 2.8 1.2 1.4
app3 5.5 5.0 3.5 4.4 5.4 5.6 5.3 4.4 5.2 4.3 4.2
file3 has the similar structure and values...
There are eight such files, and when I use the function mean(file1, file2,
file3, ..., file8), it returns the error below. Thanks for your help.
Warning message:
In mean.default(file1, file2, file3, file4, file5, file6, file7, :
argument is not numeric or logical: returning NA
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