As Chris points out, we do not know what the factor labels were before you
tried to change them. The levels() function should have worked as long as it
included all of the factor levels in the same order. The names() function lists
the names of an object. For a data frame that is the column headings. Vectors
like ind.davis$Ageclass do not have names:
> set.seed(42) # Create some random data
> ind.davis <- data.frame(ID=1:10, Ageclass=sample(c("A", "J", "S"), 10,
> replace=TRUE))
> str(ind.davis)
'data.frame': 10 obs. of 2 variables:
$ ID : int 1 2 3 4 5 6 7 8 9 10
$ Ageclass: Factor w/ 3 levels "A","J","S": 3 3 1 3 2 2 3 1 2 3
> levels(ind.davis$Ageclass)
[1] "A" "J" "S"
> names(ind.davis$Ageclass)
NULL
> names(ind.davis)
[1] "ID" "Ageclass"
> levels(ind.davis$Ageclass) <- c("Adult", "Juvenile", "Sub-adult")
> levels(ind.davis$Ageclass)
[1] "Adult" "Juvenile" "Sub-adult"
> str(ind.davis)
'data.frame': 10 obs. of 2 variables:
$ ID : int 1 2 3 4 5 6 7 8 9 10
$ Ageclass: Factor w/ 3 levels "Adult","Juvenile",..: 3 3 1 3 2 2 3 1 2 3
-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-----Original Message-----
From: R-help [mailto:[email protected]] On Behalf Of Christopher W
Ryan
Sent: Tuesday, June 20, 2017 8:23 AM
To: R-help <[email protected]>
Subject: Re: [R] Help
Leonardo--
R-help can be a very useful resource. Some suggestions to use it well:
1. use an informative subject line, not "help"
2. include a "minimal working example:" a *little* data, the code that,
with those data, reproduces your problem, and the error message that
resulted.
As to your particular question, at this point I can only guess, but for
starters it would probably help to show the output of
str(ind.davis)
--Chris Ryan
On Tue, Jun 20, 2017 at 1:06 AM, Leonardo Malaguti <
[email protected]> wrote:
> Dear expert friends,
> I'm pretty young of this world and my question at your eyes can be petty
> easy.
> I'll need to change the name of the levels inside a column of my data-frame
>
> levels(ind.davis$Ageclass) <- c("adult", "Juvanile", "sub-adult")
> names(ind.davis$Ageclass) <- c("Adult", "Juvenile", "Sub-adult")
> that is what I tried but of course doesn't work.
>
> Thanks,
> have a wonderful day,
> Leo
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> [email protected] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/
> posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
