Your code doesn't make sense to me in a couple of ways.
Inside the loop, the first line assigns a value to an object named "t".
Then, the second line does the same thing, assigns a value to an object
named "t".
The value of the object named "t" after the second line will be the output
of the ifelse() expression, whatever that is. This has the effect of making
the first line irrelevant. Whatever value t has after the first line is
replaced by whatever it gets from the second line.
It looks like the first line inside the loop is constructing the name of a
data frame column, and storing that name as a character string. However,
the second line doesn't use that name at all. If your goal is to update the
contents of a column, you need to assign something to that column in the
next line. Instead you assign it to the object named "t".
What you're looking for will be more along the lines of this:
for (i in 1:10){
nm <- paste0("V", i)
d0[[nm]] <- ifelse( regexpr(d1[i,1], d0$X0) > 0, 1, 0)
}
This may not a complete solution, since I have no idea what the contents
or structure of d1 are, or what the regexpr() is expected to return.
And notice the use of double brackets, [[ and ]]. This is one way to
reference a column of a data frame when you have the column's name stored
in a variable. Another way is d0[ , nm]
A couple of additional comments:
"t" is a poor choice of object name, because it is one of R's built-in
functions (immediately after starting a fresh session of R, with nothing
left over from any previous session, type help("r") and see what you get).
ifelse() is intended for use on vectors, not scalars, and it looks like
maybe you're using it on a scalar (can't be sure about this, though)
For example, ifelse() is designed for this kind of usage:
ifelse( c(TRUE, FALSE, TRUE) , 1:3, 11:13)
[1] 1 12 3
Although it works ok for these
ifelse(TRUE, 3, 4)
[1] 3
ifelse(FALSE, 3, 4)
[1] 4
They are not really what it is intended for.
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
Lab cell 925-724-7509
On 4/24/18, 12:30 AM, "R-help on behalf of Luca Meyer" <
[email protected] on behalf of [email protected]> wrote:
Hi,
I am trying to debug the following code:
for (i in 1:10){
t <- paste("d0$V",i,sep="")
t <- ifelse(regexpr(d1[i,1],d0$X0)>0,1,0)
}
and I would like to see what code is actually processing R, how can I
do
that?
More to the point, I am trying to update my variables d0$V1 to d0$V10
according to the presence or absence of some text (contained in the
file
d1) within the d0$X0 variable.
The code seem to run ok, if I add print(table(t)) within the loop I
can see
that the ifelse procedure is working and to some cases within the
d0$V1 to
d0$V10 variable range a 1 is assigned. But when checking my d0$V1 to
d0$V10
after the for loop they are all still equal to zero...
Thanks,
Luca
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