Sorry about the last incomplete post. Accidentally hit send.

Meant to say that I was hoping that a correct, but  obscure response from me 
would motivate David to step back and think about his problem long enough to 
see that it has an easy solution.

Sorry if that was out-of-line.

Chuck

> On Jul 6, 2018, at 4:27 PM, Charles Berry <[email protected]> wrote:
> 
>> On Jul 6, 2018, at 3:31 PM, Duncan Murdoch <[email protected]> wrote:
>> 
>> On 06/07/2018 1:18 PM, Berry, Charles wrote:
>>> A liitle math goes along way. See below.
>>>> On Jul 5, 2018, at 10:35 PM, Marino David <[email protected]> wrote:
>>>> 
>>>> Dear Bert,
>>>> 
>>>> I know it is a simple question. But for me, at current, I fail to implement
>>>> it. So, I ask for help here.
>>>> 
>>>> It is not homework.
>>>> 
>>>> Best,
>>>> 
>>>> David
>>>> 
>>>> 2018-07-06 13:32 GMT+08:00 Bert Gunter <[email protected]>:
>>>> 
>>>>> Is this homework?
>>>>> 
>>>>> (There is an informal no-homework policy on this list).
>>>>> 
>>>>> Cheers,
>>>>> Bert
>>>>> 
>>>>> 
>>>>> 
>>>>> Bert Gunter
>>>>> 
>>>>> "The trouble with having an open mind is that people keep coming along and
>>>>> sticking things into it."
>>>>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>>>>> 
>>>>> On Thu, Jul 5, 2018 at 10:23 PM, Marino David <[email protected]>
>>>>> wrote:
>>>>> 
>>>>>> Dear All,
>>>>>> 
>>>>>> I would like to generate N random Bernoulli draws given a probability
>>>>>> function F(x)=1-exp(-2.5*x) in which x follows  uniform distribution, say
>>>>>> x~U(0,2).
>>> If each Bernoulli draw is based on its own draw of x, then
>>>     rbinom( N, 1, 0.8013476 )
>>> is what you want.
>>> It is left as an exercise for the reader to verify that the constant 
>>> 0.8013476 is correct up to approximation error, and to prove that such a 
>>> Bernoulli mixture is also Bernoulli. Perhaps,
>>>     ?integrate
>>> will help.
>>> But if the x's are shared you need to use runif, expm1, and (possibly) rep 
>>> to produce a vector to be used in place of the prob argument.
> 

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