Hello, Eric is right but...
You have two assignments. The second sets a value that will be overwritten is the next iteration by myMatrix[i,i] = -1 when 'i' becomes the next value.
If you fix the second index and use 'j', you might as well do myMatrix[] = -1 myMatrix[, ncol(myMatrix)] = 1 Hope this helps, Rui Barradas Às 10:24 de 06/08/2018, Eric Berger escreveu:
Both loops are on 'i', which is a bad idea. :-) Also myMatrix[i,i+1] will be out-of-bounds if i = ncol(myMatrix) On Mon, Aug 6, 2018 at 12:02 PM, Maija Sirkjärvi <[email protected]> wrote:I have a basic for loop with a simple matrix. The code is doing what it is supposed to do, but I'm still wondering the error "subscript out of bounds". What would be a smoother way to code such a basic for loop? myMatrix <- matrix(0,5,12) for(i in 1:nrow(myMatrix)) { for(i in 1:ncol(myMatrix)) { myMatrix[i,i] = -1 myMatrix[i,i+1] = 1 }} print(myMatrix) Thanks in advance! [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/ posting-guide.html and provide commented, minimal, self-contained, reproducible code.[[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ [email protected] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
