"Is there any way ..."
Two quick answers:
1. using base R functions and data types the answer is 'no' - a double
(i.e. numeric) contains about 15 significant digits.
So 5.678e-100 is fine but 0.01 + 5.678e-100 will keep the
.0100000000000000 as the significant digits and "drop" the digits 80 or so
places further to the right.
2. there are packages that provide for arbitrary precision calculations
see R CRAN package Rmpfr
https://cran.r-project.org/web/packages/Rmpfr/vignettes/Rmpfr-pkg.pdf
HTH,
Eric
On Fri, Mar 8, 2019 at 2:39 PM akshay kulkarni <[email protected]>
wrote:
> dear members....
> here is a piece of my code:
>
> > tail(YLf14,15)
> [1] 5.706871e-217 2.563877e-218 2.823295e-218 2.694622e-222 1.777409e-226
> [6] 1.134403e-201 5.269464e-215 2.272121e-219 2.794970e-223 1.630978e-187
> [11] 1.721529e-213 5.859815e-178 4.842612e-222 1.333685e-193 1.256051e-174
> > YLf16 <- YLf14 + 0.001
> > tail(YLf16,15)
> [1] 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001 0.001
> 0.001
> [13] 0.001 0.001 0.001
>
> Is there any way to avoid the rounding off of YLf16 to 0.001, and take
> exact values?
>
> very many thanks for your time and effort......
> yours sincerely,
> AKSHAY M KULKARNI
>
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
>
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______________________________________________
[email protected] mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
