Perfect!
Thanks a lot.
Lorenzo
On Fri, Apr 26, 2019 at 04:06:49PM +0100, Rui Barradas wrote:
Hello,
Something like this?
Map(function(y) {subset(tt2, year >= y)}, 2001:2018)
Or this?
mapply(function(y) {subset(tt2, year >= y)}, 2001:2018, SIMPLIFY = FALSE)
Hope this helps,
Rui Barradas
Às 15:51 de 26/04/19, Lorenzo Isella escreveu:
Dear All,
I must be drowning in a glass of water.
Consider the following data set
tt2<-structure(list(year = c(2000, 2001, 2002, 2003, 2004, 2005,
2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016,
2017, 2018), country = c("DE", "DE", "DE", "DE", "DE", "DE", "DE",
"DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE", "DE",
"DE"), berd = c(35600, 36331.9, 36950, 38029, 38363, 38651.038,
41148, 43034, 46073, 45275, 46929, 51077.2, 53790.1, 53566.2,
56996.5, 60952, 62826, 68644, NA)), row.names = c(NA, -19L), class =
c("tbl_df", "tbl", "data.frame"))
I would like to obtain a list of it, where every element of the list
contains the subset of tt2 for which year>=2000,
year>=2001....year>=2018 etc...
It seems something I can tackle with map or map2 from purrr, but so
far I am banging my head against the wall.
Anyone can help me?
Regards
Lorenzo
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