Yes, you are right (and yours is one of the possible cases).
I think this works (I resorted to pen and paper for once)
generate_k <- function(N, n3){
n1 <- 2+n3
n2 <- N-n1-n3
out <- c(rep(1, n1), rep(2, n2), rep(3, n3))
return(out)
}
where N is the length of the sample, n3 is the number of times I have the
number 3 in the sample (n1 and n2 are the same for 1 and 2, respectively).
So far it holds!
L.
On Thu, Aug 01, 2019 at 12:37:47PM +0200, Gerrit Eichner wrote:
n_1 + ... + n_N = 2(N-1) is requested for integers n_i >= 1.
What about c(rep(2, N-2), 1, 1))?
but I'm afraid that this was not what you really wanted. ;-)
However, you didn't say if your sample should be random. :-)
Best regards -- Gerrit
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Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
http://www.uni-giessen.de/eichner
---------------------------------------------------------------------
Am 01.08.2019 um 12:27 schrieb Lorenzo Isella:
Dear All,
I cannot unfortunately provide any R code, otherwise I
would not need to post this in the first place.
I need to generate a sample of N positive non-zero
integers such that their mean is *exactly* 2(N-1)/N,
i.e. the mean depends on the length of the sample.
For a start, we can assume that every integer in my
sample can assume only the values 1, 2 and 3.
Any suggestion is appreciated.
Cheers
Lorenzo
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