Great ! You have helped to solve a problem on which I was sweating
(sporadically, however) since months...
Thanks,
Best,
Le 20/10/2019 à 18:29, Bert Gunter a écrit :
> The legend must be "an expression vector."
> c("Sans renard",bquote(.(densren) (ind./km)^2)) is not because the
> first element is a character string.
>
> This works:
>
> plot(1:100,1:100,type="n")
> legend(list(x=0,y=100),legend=c(expression("Sans
> renard"),bquote(.(densren)
> (ind./km)^2)),lty=c(1,2),col=c("black","red"),bty="n")
>
> Cheers,
> Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Sun, Oct 20, 2019 at 9:02 AM Patrick Giraudoux
> <patrick.giraud...@univ-fcomte.fr
> <mailto:patrick.giraud...@univ-fcomte.fr>> wrote:
>
> Thanks Bert and Peter,
>
> Yes Bert, I was aware of the legend() function syntax, and just
> quoting the legend argument within the function.
>
> However, Bert and Peter, I do not understand why it works with
> your absolutely reproducible examples and not in the slightly (not
> so slightly apparently) different context where I used it...
>
> densren=1.25
> plot(1:100,1:100,type="n")
> legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren)
> (ind./km)^2)),lty=c(1,2),col=c("black","red"),bty="n")
>
> densren=1.25
> plot(1:100,1:100,type="n")
> legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren) *
> " ind."/"km"^2)),lty=c(1,2),col=c("black","red"),bty="n"
>
> Probably because the result of bquote() is concatenated in a
> character vector, but how to deal with this ?
>
> Best,
>
> Patrick
>
>
>
> Le 20/10/2019 à 16:42, Bert Gunter a écrit :
>> Assuming you are using base graphics, your syntax for adding the
>> legend appears to be wrong.
>> legend() is a separate function, not a parameter of plot.default
>> afaics.
>>
>> The following works for me:
>>
>> > densren <- 1.25
>> > plot(1:10)
>> > legend (x="center", legend =bquote(.(densren) (ind./km)^2))
>>
>> See ?legend
>>
>> Bert Gunter
>>
>> "The trouble with having an open mind is that people keep coming
>> along and sticking things into it."
>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>>
>>
>> On Sun, Oct 20, 2019 at 5:30 AM Patrick Giraudoux
>> <patrick.giraud...@univ-fcomte.fr
>> <mailto:patrick.giraud...@univ-fcomte.fr>> wrote:
>>
>> Dear listers,
>>
>> I am trying to pass an expression inlcuding a variable and a
>> superpscript to a legend. What I want to obtain is e.g. with
>> densren = 1.25
>>
>> 1.25 ind./km^2
>>
>> I have tried many variants of the following:
>>
>> legend=bquote(.(densren) (ind./km)^2)
>>
>> but if not errors, do obtain
>>
>> 1.25 (ind./km^2)
>>
>> hence not what I want (no parenthesis, 2 in superscript...)
>>
>> Any idea about a correct syntax to get what I need ?
>>
>> Best,
>>
>> Patrick
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org <mailto:R-help@r-project.org> mailing
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible
>> code.
>>
>
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