Well, actually, what I really want is a way to quickly find the fragment that
contained equal number of "(" and ")", starting from the end of the character.
In the case of
frg = ="((D:41.04,I:41.04):45.05,(((E:2.32,((G:0.67,J:0.67):0.44,H:1.11):1.21)"
that means finding the part: "(E:2.32,((G:0.67,J:0.67):0.44,H:1.11):1.21)"
automatically!
Thanks a lot!
Hua
--- On Mon, 7/14/08, Hua Li <[EMAIL PROTECTED]> wrote:
> From: Hua Li <[EMAIL PROTECTED]>
> Subject: [R] position of a specific character
> To: "R-help" <r-help@r-project.org>
> Date: Monday, July 14, 2008, 6:57 PM
> Hi All,
>
> I'm wondering whether there is a quick way to know the
> position of a specific charcater in a long character:
>
> for example
>
> frg="((D:41.04,I:41.04):45.05,(((E:2.32,((G:0.67,J:0.67):0.44,H:1.11):1.21)"
>
> and I would like to know that the 1st, 2nd, 26th, 27th,
> 28th ... character is "(", is there a quick way
> to do that?
>
> Thanks!
>
> Hua
>
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