Dear Andrew,
It's not the best solution but it does what you need:
a <- data.frame(var.1 = 1:5)
b <- data.frame(var.1 = 11:15)
test.list <- list(a=a, b=b)
res=do.call(rbind,test.list)
res$var.2=substr(rownames(res),1,1)
rownames(res)=NULL
res
HTH,
Jorge
On Fri, Jul 18, 2008 at 6:21 PM, Andrew Yee <[EMAIL PROTECTED]> wrote:
> In the following code, I'd like to be able to create a new variable
> containing the value of the names of the list.
>
>
> a <- data.frame(var.1 = 1:5)
> b <- data.frame(var.1 = 11:15)
>
> test.list <- list(a=a, b=b)
>
> # in this case, names(test.list) is "a" and "b"
>
> # and I'd like to use lapply() so that
> # I get something that looks like
> # var.1 var.2
> # 1 a
> # 2 a
> # 3 a
> #etc.
>
> new.list <- lapply(test.list, function(x) {x$var.2 <- names(x)
> x} )
>
>
> # the above clearly doesn't do it. How do you pull out the names of the
> thing that is being lapplied?
>
> Thanks,
> Andrew
>
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>
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> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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