Sure John, df1<-df1[order(as.character(df1$year),decreasing=TRUE),]
Jim On Tue, Nov 10, 2020 at 8:05 PM John <miao...@gmail.com> wrote: > Thanks Jim. Can we do descending order? > > Jim Lemon <drjimle...@gmail.com> 於 2020年11月10日 週二 下午4:56寫道: > >> Hi John, >> >> df1<-sapply(df1,as.character) >> >> Should do what you ask. The error message probably means that you should >> do this: >> >> df1<-df1[order(as.character(df1$year)),] >> >> as "year" is the name of the first column in df1, not a separate object. >> >> Jim >> >> On Tue, Nov 10, 2020 at 6:57 PM John <miao...@gmail.com> wrote: >> >>> Hi, >>> >>> I would like to sort the following simple dataframe by "year" >>> (characters), but the factor structure prevents me from doing so. How >>> can I >>> remove the factor structure? Thanks! >>> >>> > df1 >>> year country >>> 4 2007 Asia; survey >>> 5 2010 8 countries in E/SE Asia >>> 6 2015 Ghana >>> 7 >>> 8 2000 US? >>> > str(df1) >>> 'data.frame': 5 obs. of 2 variables: >>> $ year : Factor w/ 9 levels "2017","2016",..: 4 5 3 6 7 >>> $ country: Factor w/ 9 levels "Euro Area\\newline Testing the MP >>> performance of the Euro Area",..: 4 5 6 7 8 >>> > df1[order(-year), ] >>> Error in order(-year) : object 'year' not found >>> >>> [[alternative HTML version deleted]] >>> >>> ______________________________________________ >>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> >> [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.