No. I wrote the function so I am sure no "invisible" command was used.
Strangely enough, compiling the function isto part of a package, results
were NOT printed. Yes if I call the function during run, by preceding
the call with a line that attach the source code:
source("A:/.../R/oprobit.R")
it did print. I do not understand.
On 2020/11/30 下午 06:41, Stefan Evert wrote:
On 30 Nov 2020, at 10:41, Steven Yen <st...@ntu.edu.tw> wrote:
Thanks. I know, my point was on why I get something printed by simply doing
line 1 below and at other occasions had to do line 2.
me.probit(obj)
That means the return value of me.probit() has been marked as invisible, so it
won't auto-print. You have to use an explicit print
print(me.probit(obj))
or use your work-around to convince R that you actually meant to print the
output.
If you dig through the full code of me.probit(), you'll probably find the
function invisible() called somewhere.
Best,
Stefan
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