On Mon, 23 Aug 2021 08:37:54 +0200
Dr Eberhard Lisse <[email protected]> wrote:
> create the variables dynamically and add them to to
> the grid (dynamically, ie adding more countries)
In my opinion, creating variables in the global environment
programmatically may lead to code that is hard to understand and debug
[*]. A key-value data structure (a named list or a separate
environment) would avoid the potential problems from variable name
collision. How about the following:
1. Put the countries in a vector: c('Namibia', 'Germany', ...)
2. Use lapply() to get a list of objects returned from your PICTURE
function
3. To save the pictures into individual files, loop over the list. You
can use setNames on the step 1 or 2 to make it a named list and keep
the country names together with their pictures:
for (n in names(pictures)) {
dev.new()
print(pictures[[n]])
ggsave(paste0(n, '.png'), ...)
dev.off()
}
(You can also use the png() device and plot straight to the file,
avoiding the need to draw the plot in the window for a fraction of a
second and for ggsave().)
4. Use the grobs= argument of grid.arrange() to pass the list of
objects to arrange instead of passing individual objects via ...
--
Best regards,
Ivan
[*] For example, there's this FAQ for a different language:
https://perldoc.perl.org/perlfaq7#How-can-I-use-a-variable-as-a-variable-name?
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