Re: [R] Problem with data distribution

Rui Barradas Thu, 17 Feb 2022 11:35:40 -0800

Hello,

In your original post you read the same file "synapse.arff" twice,apparently to filter each of them by its own criterion. You don't needto do that, read once and filter that one by different criteria.


As for the data as posted, I have read it in with the following code:


x <- "

0 1 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0 1 0 0 0 0 0 04 1 00 1 0 0 0 0 0 0 1 0 3 2 0 0 0 0 3 0 0 0 0 2 0 0 0 1 0 0 0 0 1 1 1 0 0 00 0 01 1 2 1 0 1 0 0 0 2 2 1 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 5 0 0 0 0 0 0 70 0 10 1 1 0 2 0 3 0 1 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 3 2 1 1 0 0 0 0 0 0 01 0 00 0 0 0 0 0 0 0 0 1 0 1 0 0 3 0 0 1 0 1 3 0 0 0 0 0 0 0 0 1 0 4 1 1 0 00 0 1

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 1 0 0 0 0 0
"
bug <- scan(text = x)
data <- data.frame(bug)

This is not the right way to post data, the posting guide asks to postthe output of



dput(data)
structure(list(bug = c(0, 1, 0, 0, 0, 1, 2, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 0, 0, 0, 0, 1, 0, 0, 0, 0,
0, 0, 4, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 3, 2, 0, 0, 0, 0,
3, 0, 0, 0, 0, 2, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0,
0, 0, 1, 1, 2, 1, 0, 1, 0, 0, 0, 2, 2, 1, 1, 0, 0, 0, 0, 0, 0,
1, 0, 0, 1, 0, 0, 1, 0, 0, 5, 0, 0, 0, 0, 0, 0, 7, 0, 0, 1, 0,
1, 1, 0, 2, 0, 3, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0,
0, 1, 0, 3, 2, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 3, 0, 0, 1, 0, 1, 3, 0, 0, 0, 0,
0, 0, 0, 0, 1, 0, 4, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 0, 1, 0, 0, 0, 0, 0)),
class = "data.frame", row.names = c(NA, -222L))



This can be copied into an R session and the data set recreated with

data <- structure(etc)


Now the boxplots.

(Why would you want to plot a vector of all zeros, btw?)



library(dplyr)

boxplot(filter(data, bug == 0))    # nonsense
boxplot(filter(data, bug > 0), range = 0)

# Another way
data %>%
  filter(bug > 0) %>%
  boxplot(range = 0)


Hope this helps,

Rui Barradas


Às 19:03 de 17/02/2022, Neha gupta escreveu:

That is all the code I have. How can I provide a  reproducible code ?

How can I save this result?

On Thu, Feb 17, 2022 at 8:00 PM Ebert,Timothy Aaron <teb...@ufl.edu> wrote:

You pipe the filter but do not save the result. A reproducible example
might help.
Tim

-----Original Message-----
From: R-help <r-help-boun...@r-project.org> On Behalf Of Neha gupta
Sent: Thursday, February 17, 2022 1:55 PM
To: r-help mailing list <r-help@r-project.org>
Subject: [R] Problem with data distribution

[External Email]

Hello everyone

I have a dataset with output variable "bug" having the following values
(at the bottom of this email). My advisor asked me to provide data
distribution of bugs with 0 values and bugs with more than 0 values.

data = readARFF("synapse.arff")
data2 = readARFF("synapse.arff")
data$bug
library(tidyverse)
data %>%
   filter(bug == 0)
data2 %>%
   filter(bug >= 1)
boxplot(data2$bug, data$bug, range=0)

But both the graphs are exactly the same, how is it possible? Where I am
doing wrong?

data$bug
   [1] 0 1 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0 1 0 0 0 0 0
0 4 1 0
  [40] 0 1 0 0 0 0 0 0 1 0 3 2 0 0 0 0 3 0 0 0 0 2 0 0 0 1 0 0 0 0 1 1 1 0 0
0 0 0 0
  [79] 1 1 2 1 0 1 0 0 0 2 2 1 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 5 0 0 0 0 0 0
7 0 0 1
[118] 0 1 1 0 2 0 3 0 1 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 3 2 1 1 0 0 0 0 0 0
0 1 0 0
[157] 0 0 0 0 0 0 0 0 0 1 0 1 0 0 3 0 0 1 0 1 3 0 0 0 0 0 0 0 0 1 0 4 1 1 0
0 0 0 1
[196] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 1 0 0 0 0 0

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and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.


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Re: [R] Problem with data distribution

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