I (maybe) agree, but I would go further than that. There are assumptions 
associated with the test that are missing. It is not clear that the 
relationships are all linear. Regardless of a "significant outcome" all of the 
relationships need to be explored in more detail than what is provided in the 
correlation test.

Multiplicity adjustment as in : 
https://www.sciencedirect.com/science/article/pii/S0197245600001069 is not an 
issue that I can see in these data from the information provided. At least not 
in the same sense as used in the link.

My first guess at the meaning of "multiplicity adjustment" was closer to the 
experimentwise error rate in a multiple comparison procedure. 
https://dictionary.apa.org/experiment-wise-error-rateEssentially, the type 1 
error rate is inflated the more test you do and if you perform enough tests you 
find significant outcomes by chance alone. There is great significance in the 
Redskins rule: https://en.wikipedia.org/wiki/Redskins_Rule.

A simple solution is to apply a Bonferroni correction where alpha is divided by 
the number of comparisons. If there are 250, then 0.05/250 = 0.0002. Another 
approach is to try to discuss the outcomes in a way that makes sense. What is 
the connection between a football team's last home game an the election result 
that would enable me to take another team and apply their last home game result 
to the outcome of a different election?

Another complication is if variables x2 through x250 are themselves correlated. 
Not enough information was provided in the problem to know if this is an issue, 
but 250 orthogonal variables in a real dataset would be a bit unusual 
considering the experimentwise error rate previously mentioned.

Large datasets can be very messy.


Tim

-----Original Message-----
From: Bert Gunter <bgunter.4...@gmail.com> 
Sent: Monday, August 22, 2022 12:07 PM
To: Ebert,Timothy Aaron <teb...@ufl.edu>
Cc: Val <valkr...@gmail.com>; r-help@R-project.org (r-help@r-project.org) 
<r-help@r-project.org>
Subject: Re: [R] Correlate

[External Email]

... But of course the p-values are essentially meaningless without some sort of 
multiplicity adjustment.
(search on "multiplicity adjustment" for details). :-(

-- Bert


On Mon, Aug 22, 2022 at 8:59 AM Ebert,Timothy Aaron <teb...@ufl.edu> wrote:
>
> A somewhat clunky solution:
> for(i in colnames(dat)){
>   print(cor.test(dat[,i], dat$x1, method = "pearson", use = 
> "complete.obs")$estimate)
>   print(cor.test(dat[,i], dat$x1, method = "pearson", use = 
> "complete.obs")$p.value) }
>
> Rather than printing you could set up an array or list to save the results.
>
>
> Tim
>
> -----Original Message-----
> From: R-help <r-help-boun...@r-project.org> On Behalf Of Val
> Sent: Monday, August 22, 2022 11:09 AM
> To: r-help@R-project.org (r-help@r-project.org) <r-help@r-project.org>
> Subject: [R] Correlate
>
> [External Email]
>
> Hi all,
>
> I have a data set with  ~250  variables(columns).  I want to calculate 
> the correlation of  one variable with the rest of the other variables 
> and also want  the p-values  for each correlation.  Please see the 
> sample data and my attempt.  I  have got the correlation but unable to 
> get the p-values
>
> dat <- read.table(text="x1 x2 x3 x4
>            1.68 -0.96 -1.25  0.61
>           -0.06  0.41  0.06 -0.96
>               .    0.08  1.14  1.42
>            0.80 -0.67  0.53 -0.68
>            0.23 -0.97 -1.18 -0.78
>           -1.03  1.11 -0.61    .
>            2.15     .    0.02  0.66
>            0.35 -0.37 -0.26  0.39
>           -0.66  0.89   .    -1.49
>            0.11  1.52  0.73  -1.03",header=TRUE)
>
> #change all to numeric
>     dat[] <- lapply(dat, function(x) as.numeric(as.character(x)))
>
>     data_cor <- cor(dat[ , colnames(dat) != "x1"],  dat$x1, method = 
> "pearson", use = "complete.obs")
>
> Result
>               [,1]
> x2 -0.5845835
> x3 -0.4664220
> x4  0.7202837
>
> How do I get the p-values ?
>
> Thank you,
>
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