Thank you. I'll try this. --- Kai
On Friday, September 16, 2022 at 11:01:33 AM PDT, Rui Barradas
<ruipbarra...@sapo.pt> wrote:
Hello,
Something like the following might work.
filenames <- list.files(pattern = "^file\\d+\\.txt$")
destnames <- sapply(filenames, scan, what = character(), sep = "\n", n =
1L, strip.white = TRUE)
if(length(filenames) == length(destnames))
file.rename(filenames, destnames)
else message("something went wrong")
But I would make copies of 2 or 3 files first and test with, say,
filenames[1:2] and destnames[1:2]
Hope this helps,
Rui Barradas
Às 18:51 de 16/09/2022, Kai Yang escreveu:
> Hello,Here is the example:
> file name first row file1.txt abc.txt file2.txt bed.txt
>file3.txt gogo.txt . . file1243.txt last.txt
> I want to use loop because I need to read the first row information for first
> file, and then rename the file, then go to next file. I'm not sure if this is
> right way to approach my goal. Any suggestion will be appreciated. Thanks,
> Kai On Friday, September 16, 2022 at 10:38:32 AM PDT, Rui Barradas
> <ruipbarra...@sapo.pt> wrote:
>
> Hello,
>
> Please post the first row of 2 or 3 files and the expected result.
>
> You can rename files with ?file.rename. This function is vectorized its
> on arguments so you do not need a loop, only the source and destination
> filenames. Both vectors should have the same length, if not strange
> things will occur including data loss.
>
> Hope this helps,
>
> Rui Barradas
>
> Às 18:26 de 16/09/2022, Kai Yang via R-help escreveu:
>> Hello,I have a lot of files with not meaningful name, such as: file1.txt,
>> file2.txt ...... I need to rename them using the information from the first
>> row of the files. Now I can get the information from the first row of each
>> file. Now, I need know how to rename them in R (using loop?). Thank you for
>> your helpKai
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>
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