Hello,
Às 09:42 de 21/04/2023, Jeff Newmiller escreveu:
0
Somewhat cryptic...
Rui Barradas
On April 21, 2023 4:08:08 AM GMT+09:00, Dr Eberhard W Lisse <nos...@lisse.na>
wrote:
There is at least one outliers package on CRAN.
el
On 20/04/2023 20:43, AbouEl-Makarim Aboueissa wrote:
Dear All: *please discard my previous email*
*Re:* detect and replace outliers by the average
The dataset, please see attached, contains a group factoring column “
*factor*” and two columns of data “x1” and “x2” with some NA values. I need
some help to detect the outliers and replace it and the NAs with the
average within each level (0,1,2) for each variable “x1” and “x2”.
I tried the below code, but it did not accomplish what I want to do.
data<-read.csv("G:/20-Spring_2023/Outliers/data.csv", header=TRUE)
data
replace_outlier_with_mean <- function(x) {
replace(x, x %in% boxplot.stats(x)$out, mean(x, na.rm=TRUE)) #### ,
na.rm=TRUE NOT working
}
data[] <- lapply(data, replace_outlier_with_mean)
Thank you all very much for your help in advance.
with many thanks
abou
______________________
*AbouEl-Makarim Aboueissa, PhD*
*Professor, Mathematics and Statistics*
*Graduate Coordinator*
*Department of Mathematics and Statistics*
*University of Southern Maine*
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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