Reading the doc for ?simplify2array, I got the impression that with the
'higher = T' argument the function returns an array of dimension greater
than 2 when it makes sense (the doc says "when appropriate", which is
rather vague). I would expect
a <- list(
list(list(1, 2), list(3, 4)),
list(list(5, 6), list(7, 8))
)
simplify2array(a, higher = T)
to return the same (possibly up to a dimension permutation) as
array(1:8, dim = c(2, 2, 2))
However, in this case simplify2array returns a matrix (i.e. 2 dimensional
array), whose elements are lists.
It's the same as
structure(list(list(1, 2), list(3, 4), list(5, 6), list(7, 8)), dim = c(2,
2))
I get the same behavior with
a <- list(
list(c(1, 2), c(3, 4)),
list(c(5, 6), c(7, 8))
)
but then the matrix elements are numeric vectors instead of lists.
Did I miss something to get the result I expected with this function? Or is
it a bug? Or maybe the function is not supposed to return a higher
dimensional array, and I didn't understand the documentation correctly?
There is a workaround, one can do for instance
array(unlist(a), dim = c(2, 2, 2))
and there may be better options (checking dimensions?).
In case it's important: running R 4.3.2 on Debian 12.4.
Best regards,
Jean-Claude Arbaut
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