Hi Dennis,

look at the help page for summary.survfit, the Value n.event.

Göran

On 2024-05-15 22:41, Dennis Fisher wrote:
OS X
R 4.3.3

Colleagues

I have created objects using the Surv function in the survival package:
FIT.1
Call: survfit(formula = FORMULA1)

                                        n events median 0.95LCL 0.95UCL
SUBDATA$ARM=1, SUBDATA[, EXP.STRAT]=0 18     13    345     156      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=1 13      5     NA     186      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=2  5      5    168      81      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=3  1      1     22      NA      NA

I am interested in extracting the “n” and “events” values.
“n” is easy:
FIT.1[[1]]
[1] 18 13  5  1

or
FIT.1$n
[1] 18 13  5  1

But I can’t figure out how to access “events”.

str(FIT.1) provides no insights:
List of 17
  $ n        : int [1:4] 18 13 5 1
  $ time     : num [1:37] 45 106 107 124 152 156 170 176 319 371 ...
  $ n.risk   : num [1:37] 18 17 16 15 14 13 12 11 10 9 ...
  $ n.event  : num [1:37] 1 1 1 1 1 1 1 1 1 1 ...
  $ n.censor : num [1:37] 0 0 0 0 0 0 0 0 0 0 ...
  $ surv     : num [1:37] 0.944 0.889 0.833 0.778 0.722 ...
  $ std.err  : num [1:37] 0.0572 0.0833 0.1054 0.126 0.1462 ...
  $ cumhaz   : num [1:37] 0.0556 0.1144 0.1769 0.2435 0.315 ...
  $ std.chaz : num [1:37] 0.0556 0.0809 0.1022 0.1221 0.1414 ...
  $ strata   : Named int [1:4] 18 13 5 1
   ..- attr(*, "names")= chr [1:4] "SUBDATA$ARM=1, SUBDATA[, EXP.STRAT]=0" "SUBDATA$ARM=2, SUBDATA[, 
EXP.STRAT]=1" "SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=2" "SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=3"
  $ type     : chr "right"
  $ logse    : logi TRUE
  $ conf.int : num 0.95
  $ conf.type: chr "log"
  $ lower    : num [1:37] 0.844 0.755 0.678 0.608 0.542 ...
  $ upper    : num [1:37] 1 1 1 0.996 0.962 ...
  $ call     : language survfit(formula = FORMULA1)
  - attr(*, "class")= chr "survfit"

If I could access:
                                        n events median 0.95LCL 0.95UCL
SUBDATA$ARM=1, SUBDATA[, EXP.STRAT]=0 18     13    345     156      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=1 13      5     NA     186      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=2  5      5    168      81      NA
SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=3  1      1     22      NA      NA
it should be easy to get “events”.

Any thoughts?

Dennis

Dennis Fisher MD
P < (The "P Less Than" Company)
Phone / Fax: 1-866-PLessThan (1-866-753-7784)
www.PLessThan.com

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