On 2024-09-26 11:55 p.m., Rolf Turner wrote:
I have (toy example):
x <- list(`1` = c(7, 13, 1, 4, 10),
`2` = c(2, 5, 14, 8, 11),
`3` = c(6, 9, 15, 12, 3))
and
f <- factor(rep(1:3,5))
I want to create a vector v of length 15 such that the entries of v,
corresponding to level l of f are the entries of x[[l]]. I.e. I want
v to equal
c(7, 2, 6, 13, 5, 9, 1, 14, 15, 4, 8, 12, 10, 11, 3)
I can create v "easily enough", using say, a for-loop. It seems to me,
though, that there should be sexier (single command) way of achieving
the desired result. However I cannot devise one.
Don't you find a for loop's naked display of intention to be sexy?
Duncan Murdoch
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