Thank you to all who applied. These all seem to work the way I want them to.
The outer function seems really useful, I probably could use that for a lot
of my work.
Thanks!
Rolf Turner-3 wrote:
>
>
> On 30/07/2008, at 6:12 AM, dxc13 wrote:
>
>>
>> useR's,
>>
>> I am trying trying to find out if there is a faster way to do a
>> certain
>> computation. I have successfully used FOR loops and the apply
>> function to
>> do this, but it can take some time to fully compute, but I was
>> wondering if
>> anyone may know of a different function or way to do this:
>>> x
>> [1] 1 2 3 4 5
>>> xk
>> [1] 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0
>>
>> I want to do: abs(x-xk[i]) where i = 1 to length(xk)=13. It should
>> result
>> in a 13 by 5 matrix or data frame. Does anyone have a "quicker"
>> solution
>> than FOR loops or apply()?
>
> outer(xk,x,function(a,b){abs(a-b)})
>
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