Not sure what you're looking for, but does this help? Extending your code,
> library(gsubfn) > t(strapply(levels(my.cuts),"([0-9.]+),([0-9.]+)", + function(...) as.numeric(c(...)),backref=-2,simplify=TRUE)) [,1] [,2] [1,] 15.9 38.3 [2,] 38.3 60.7 [3,] 60.7 83.1 ----- Original Message ---- From: baptiste auguie <[EMAIL PROTECTED]> To: r-help@r-project.org Sent: Saturday, August 9, 2008 1:51:01 AM Subject: [R] levels values of cut() Dear list, I have the following example, from which I am hoping to retrieve numeric values of the factor levels (that is, without the brackets): > > x <- seq(1, 15, length=100) > y <- sin(x) > > my.cuts <- cut(which(abs(y) < 1e-1), 3) > levels(my.cuts) hist() does not suit me for this, as it does not necessarily respect the number of breaks. getAnywhere hasn't got me very far: I cannot seem to find a readable code for the built-in cut function in the base library. I think getMethod should do it but I don't understand the arguments to pass. Any pointers appreciated, Thanks, baptiste _____________________________ Baptiste AuguiƩ School of Physics University of Exeter Stocker Road, Exeter, Devon, EX4 4QL, UK Phone: +44 1392 264187 http://newton.ex.ac.uk/research/emag ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.