Stephen and Jorge,
 Perhaps a simpler solution is to use the which function

test.data <- Harman74.cor$cov    #a test data set
td <- test.data * lower.tri(test.data) #this will examine only the lower off diagonal elements
td.1 <- which(abs(td)>.6,arr.ind=TRUE)   # the critical pairs
td.2 <- td[which(abs(td)>.6)]                       # the values
td.row <-  colnames(test.data)[td.1[,1]]  #get the row names
td.col <- colnames(test.data)[td.1[,2]]     #and the column names
td.df <- data.frame(td.row,td.col,correl = td.2)   #put it all together

Bill



At 12:57 PM -0400 9/3/08, Jorge Ivan Velez wrote:
Dear Stephen,
Perhaps this<http://www.nabble.com/Re:-applying-cor.test-to-a-(m,-n)-matrix---SUMMARY-to17150239.html#a17150239>post
could helps. In general:


# Function
correl.stats=function(X, method = "pearson", use = "complete" , conf.level =
0.95){
require(forward)
combs=t(fwd.combn(colnames(X), 2))
temp=t(apply(combs,1, function(x){
Y=X[,as.character(x)]
res=cor.test(Y[,1],Y[,2], use = use, method = method, conf.level =
conf.level)
temp2=c(res$estimate, res$statistic, res$p.value, res$conf.int[1:2])
names(temp2)=c('rho','statistic','pvalue','lower','upper')
rm(res)
temp2
}
)
)
rownames(temp)=paste(combs[,1],combs[,2],sep="")
temp
}

# Data set
set.seed(123)
m <- matrix(rnorm(10*5), ncol=5); colnames(m)=paste("m",1:ncol(m),sep="")

# Correlations
res=correl.stats(m)
res
rho   statistic     pvalue       lower      upper
m1m2  0.57761512  2.00137666 0.08034470 -0.08173768 0.88528096
m1m3 -0.40595930 -1.25641472 0.24441138 -0.82477175 0.30046722
m1m4  0.67301956  2.57371995 0.03293644  0.07530295 0.91493950
m1m5 -0.34863673 -1.05210481 0.32348990 -0.80217657 0.36001727
m2m3 -0.56734869 -1.94869211 0.08716815 -0.88193296 0.09688755
m2m4  0.27131880  0.79731302 0.44828479 -0.43212763 0.76949303
m2m5 -0.25201740 -0.73658790 0.48241166 -0.76090564 0.44882739
m3m4 -0.43726491 -1.37521060 0.20634394 -0.83657173 0.26544083
m3m5  0.02265933  0.06410673 0.95045815 -0.61575185 0.64311043
m4m5  0.07453706  0.21141075 0.83785303 -0.58242262 0.67259801


# Filtering
res[res[,'rho']>0.6,]
 rho  statistic     pvalue      lower      upper
0.67301956 2.57371995 0.03293644 0.07530295 0.91493950


HTH,

Jorge


On Wed, Sep 3, 2008 at 11:04 AM, stephen sefick <[EMAIL PROTECTED]> wrote:

 I have one hundred and six independent variable that I would like to
 preform a correlation analysis on.  Is there anyway to only get the
 values that are abolute value 0.6 or greater.
 thanks


 --
 Stephen Sefick
 Research Scientist
 Southeastern Natural Sciences Academy

 Let's not spend our time and resources thinking about things that are
 so little or so large that all they really do for us is puff us up and
 make us feel like gods. We are mammals, and have not exhausted the
 annoying little problems of being mammals.

        -K. Mullis

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