Sender: [EMAIL PROTECTED]
On-Behalf-Of: [EMAIL PROTECTED]
Subject: Re: [R] Substitute problem
Message-Id: <[EMAIL PROTECTED]>
Recipient: [EMAIL PROTECTED]
--------------------------------------------------------



This information is being sent at the recipient's request or with their 
specific understanding. The recipient acknowledges that by sending this 
information via electronic means, there is no absolute assurance that the 
information will be free from third party access, use, or further 
dissemination. This e-mail contains information that is privileged and/or 
confidential and may be subject to legal restrictions and penalties regarding 
its unauthorized disclosure or other use. You are prohibited from copying, 
distributing or otherwise using this information if you are not the intended 
recipient. Past performance is not necessarily indicative of future results. 
This is not an offer of or the solicitation for any security which will be made 
only by private placement memorandum that may be obtained from the applicable 
hedge fund. If you have received this e-mail in error, please notify us 
immediately by return e-mail and delete this e-mail and all attachments from 
your system. Thank You.
--- Begin Message ---
Thanks! Works fine!



jholtman wrote:
> 
> Had the test wrong in the last one'  try this:
> 
>> x
>   X     value     row     col ID         n
> 1 1 11.105009 5511625 3463000  1 -619.1125
> 2 2 10.324148 5499625 3465000  0    1.0000
> 3 3  8.744591 5503625 3475000  0    1.0000
> 4 4  9.523473 5494625 3475000  3 -578.2354
> 5 5  8.856097 5507625 3480000  4 -619.1125
> 6 6  8.636881 5514625 3497000  5 -140.8012
>> id_max <- 5
>> id_change <- (x$ID == 0) & (x$n > 0)
>> x$ID[id_change] <- cumsum(id_change)[id_change] + id_max
>> x
>   X     value     row     col ID         n
> 1 1 11.105009 5511625 3463000  1 -619.1125
> 2 2 10.324148 5499625 3465000  6    1.0000
> 3 3  8.744591 5503625 3475000  7    1.0000
> 4 4  9.523473 5494625 3475000  3 -578.2354
> 5 5  8.856097 5507625 3480000  4 -619.1125
> 6 6  8.636881 5514625 3497000  5 -140.8012
>>
> 
> 
> On Wed, Oct 22, 2008 at 9:06 AM, Chris82 <[EMAIL PROTECTED]> wrote:
>>
>> hello R users,
>>
>> I didn't find a solution for a special problem.
>> I have two dataframes.
>>
>> dataframe1:
>>
>>  X        value         row             col                       ID
>>  1  8.973498062         5512625         3460000         1
>>  2 11.656658570         5501625         3464000         2
>>  3 11.121777570         5495625         3473000         3
>>  4  9.310465964         5508625         3477000         4
>>  5  8.883483845         5515625         3496000         5
>>
>>
>> dataframe2:
>>
>>  X        value         row             col               ID                 
>>  
>> n
>>  1 11.105009400         5511625 3463000                   1            
>> -619.112472616732
>>  2 10.324148150         5499625 3465000                     0          
>> 1.000000000000
>>  3  8.744590903         5503625 3475000                   0            
>> 1.000000000000
>>  4  9.523473123         5494625 3475000                   3         
>> -578.235381588725
>>  5  8.856097133         5507625 3480000                     4       
>> -619.112472616732
>>  6  8.636881453         5514625 3497000                   5         
>> -140.801233634174
>>
>> Now I want if column "n" in dataframe2 is greater than 0 column "ID"
>> which
>> is 0 is now maxium column "ID" in dataframe1 +1 and the for the second 0
>> maximum + 2
>>
>> the finished dataframe2 should look like this:
>>
>>  X        value         row             col                       ID         
>>  
>> n
>>  1 11.105009400         5511625 3463000                   1      
>> -619.112472616732
>>  2 10.324148150         5499625 3465000                     6    
>> 1.000000000000
>>  3  8.744590903         5503625 3475000                   7      
>> 1.000000000000
>>  4  9.523473123         5494625 3475000                   3    
>> -578.235381588725
>>  5  8.856097133         5507625 3480000                     4  
>> -619.112472616732
>>  6  8.636881453         5514625 3497000                   5    
>> -140.801233634174
>>
>> My idea was below:
>>
>> lastrow1 <- length(dataframe2[,1])
>> lastrow2 <- length(dataframe1[,1])
>> anz <- sum(dataframe2[,6] > 0)
>>
>>
>> for (k in 1:anz){
>> for (i in 1:lastrow1){
>> for (j in 1:lastrow2){
>> if (dataframe2[i,6] > 0){
>> dataframe2[i,5] <- max(dataframe1[j,5])+(k-k+1)
>> }
>> }
>> }
>> }
>>
>>
>> but the result is:
>>
>>  X        value         row             col                       ID         
>>          
>> n
>>  1 11.105009400         5511625 3463000                   1      
>> -619.112472616732
>>  2 10.324148150         5499625 3465000                     6     
>> 1.000000000000
>>  3  8.744590903         5503625 3475000                   6       
>> 1.000000000000
>>  4  9.523473123         5494625 3475000                   3    
>> -578.235381588725
>>  5  8.856097133         5507625 3480000                     4  
>> -619.112472616732
>>  6  8.636881453         5514625 3497000                   5    
>> -140.801233634174
>>
>> R gives me the right value in the second row of "ID" with "6" but the
>> third
>> row of "ID" is also "6" but should be "7"
>>
>> any ideas?
>>
>> thanks!
>> --
>> View this message in context:
>> http://www.nabble.com/Substitute-problem-tp20110333p20110333.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
> 
> 
> 
> -- 
> Jim Holtman
> Cincinnati, OH
> +1 513 646 9390
> 
> What is the problem that you are trying to solve?
> 
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 
> 

-- 
View this message in context: 
http://www.nabble.com/Substitute-problem-tp20110333p20136308.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

--- End Message ---
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to