> Thanks, that's almost exactly what I need...theres just a slight
> difference with my requirement, in that I am looking for the actual
> index value in the alphabetical sequence, so that instead of:
>
> as.numeric(factor(unlist(strsplit("XYZ",""))))
> [1] 1 2 3
>
> I would expect to see
>
> [1] 24 25 26
A minor modeification of Mark's solution works in this case:
as.numeric(factor(unlist(strsplit("XYZ", "")), levels=LETTERS))
# [1] 24 25 26
Regards,
Richie.
Mathematical Sciences Unit
HSL
------------------------------------------------------------------------
ATTENTION:
This message contains privileged and confidential inform...{{dropped:20}}
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
