On Wed, Dec 10, 2008 at 11:02 AM, baptiste auguie <[EMAIL PROTECTED]> wrote: > Dear list, > > I have a data.frame with x, y values and a 3-level factor "group", say. I > want to create a new column in this data.frame with the values of y scaled > to 1 by group. Perhaps the example below describes it best: > >> x <- seq(0, 10, len=100) >> my.df <- data.frame(x = rep(x, 3), y=c(3*sin(x), 2*cos(x), cos(2*x)), # >> note how the y values have a different maximum depending on the group >> group = factor(rep(c("sin", "cos", "cos2"), each=100))) >> library(reshape) >> df.melt <- melt(my.df, id=c("x","group")) # make a long format >> df.melt <- df.melt[ order(df.melt$group) ,] # order the data.frame by the >> group factor >> df.melt$norm <- do.call(c, tapply(df.melt$value, df.melt$group, >> function(.v) {.v / max(.v)})) # calculate the normalised value per group and >> assign it to a new column >> library(lattice) >> xyplot(norm + value ~ x,groups=group, data=df.melt, auto.key=T) # check >> that it worked > > > This procedure works, but it feels like I'm reinventing the wheel using > hammer and saw. I tried to use aggregate, by, ddply (plyr package), but I > coudn't find anything straight-forward.
It's pretty easy with ddply: df.melt <- ddply(df.melt, .(group), transform, norm = y / max(y)) Hadley -- http://had.co.nz/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.