On Thu, 11 Dec 2008, Whit Armstrong wrote:
for a simple example:
x <- list()
x[["a"]] <- list(a=c(1,2,3),b=c(3,4,5))
x[["b"]] <- list(a=c(6,7,8),b=c(9,10,11))
lapply(x,sum)
this fails w/
Error in FUN(X[[1L]], ...) : invalid 'type' (list) of argument
Just wondering if I have overlooked something obvious.
rapply? Which is linked from ?lapply (I just checked). Perhaps
rapply(x, sum)
a.a a.b b.a b.b
6 12 21 30
or
rapply(x, sum, how="list")
$a
$a$a
[1] 6
.....
one can also do:
lapply(x,lapply,sum)
but that assumes that you already know how many levels you have, and
that all the levels are consistent.
-Whit
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--
Brian D. Ripley, rip...@stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
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