Thanks Gregor and Henrique for the eloquent and masterful replies,

These solutions have saved me hours (maybe even days) of work in the future,
I am very grateful. :-)

Simon.


----- Original Message ----- From: "Gabor Grothendieck" <[email protected]>
To: "Henrique Dallazuanna" <[email protected]>
Cc: "Simon Pickett" <[email protected]>; <[email protected]>
Sent: Thursday, December 18, 2008 11:51 AM
Subject: Re: [R] inserting zero instances with zeroes in a matrix


Try this:

as.data.frame(xtabs(count ~., d.f))


On Thu, Dec 18, 2008 at 6:25 AM, Henrique Dallazuanna <[email protected]> wrote:
Try this:

with(d.f,
   {merge(data.frame(house = rep(unique(house), each =
length(unique(pet))),
            pet = unique(pet)), d.f, by = c("house", "pet"), all = TRUE)
     }
    )

On Thu, Dec 18, 2008 at 8:58 AM, Simon Pickett <[email protected]>wrote:

Hi all,

Suppose I had the below example where a survey was carried out recording
the number of each type of pet in each house

count<-c(2,1,2,1,2,3,4)
house<-c("house1","house1","house2","house3","house4","house4","house4")
pet<-c("dogs","cats","dogs","dogs","budgie","cat","hamster")
d.f<-data.frame(house,pet,count)

How would I acheive a dataframe that had every instance of house in column
1, all possible pets in column 2 and counts in column 3 like this...

newhouse<-rep(unique(house),1,each=4)
newpets<-rep(unique(pet),4)
newcount<-c(2,1,0,0,2,0,0,0,1,0,0,0,0,3,2,4)
newdf<-data.frame(newhouse,newpets,newcount)

Is there a way of doing this without creating a new matrix and using
programming loops?

Thanks in advance, Simon.



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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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