Henrique Dallazuanna schrieb:
Try this also:
cbind(pos = mylist$df1$pos, data.frame(mylist)[grep("data",
names(data.frame(mylist)))])
Hi Henrique,
cool solution - that's seems to be the easiest way!
though I thought there should be some possibiliy of multiple merge
Anyway, this will do it for now!
Thank you!
On Wed, Jan 21, 2009 at 6:19 AM, Antje <niederlein-rs...@yahoo.de
<mailto:niederlein-rs...@yahoo.de>> wrote:
Hi there,
I have a list of dataframes (generated by reading multiple files)
and all dataframes are comparable in dimension and column names.
They also have a common column, which, I'd like to use for merging.
To give a simple example of what I have:
df1 <- data.frame(c(LETTERS[1:5]), c(2,6,3,1,9))
names(df1) <- c("pos", "data")
df3 <- df2 <- df1
df2$data <- c(6,2,9,7,5)
df3$data <- c(9,3,6,2,1)
mylist <- list(df1,df2,df3)
names(mylist) <- c("df1","df2","df3")
> mylist
$df1
pos data
1 A 2
2 B 6
3 C 3
4 D 1
5 E 9
$df2
pos data
1 A 6
2 B 2
3 C 9
4 D 7
5 E 5
$df3
pos data
1 A 9
2 B 3
3 C 6
4 D 2
5 E 1
If I use do.call("cbind"), I'll end up with something like this
pos data pos data pos data
1 A 2 A 6 A 9
2 B 6 B 2 B 3
3 C 3 C 9 C 6
4 D 1 D 7 D 2
5 E 9 E 5 E 1
but now, I don't know anymore which data comes from which
dataframe... and I have the column "pos" multiple times...
Instead I'd like to have it like this:
pos df1 df2 df3
1 A 2 6 9
2 B 6 2 3
3 C 3 9 6
4 D 1 7 2
5 E 9 5 1
How, can I realize it? (The list, I'm working with has not just 3
data frames like given in my example, so I need to automize it)
Antje
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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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