If you know the final size that your matrix will be, it is better to
preallocate the matrix, then insert the rows into the matrix:
mymat <- matrix( nrow=100, ncol=10 )
for( i in 1:100 ){
mymat[i, ] <- rnorm(10)
}
Even better than this is to use replicate or sapply if you can, they will take
all the rows created and construct the matrix for you.
The rbind way works, but it is slower and will fragment memory, so don't do
that (and don't look at the reply in another thread where I just did :-).
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Alexy Khrabrov
> Sent: Tuesday, February 24, 2009 11:02 AM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] growing dataframes with rbind
>
> I'm growing a large dataframe by composing new rows and then doing
>
> row <- compute.new.row.somehow(...)
> d <- rbind(d,row)
>
> Is this a fast/preferred way?
> Cheers,
> Alexy
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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