Better to not use c as a variable name. It's such a useful function
name.
This is what I would have tried:
col3 <- expand.grid(item=params.data$item, examinee=examinees.data
$examinee)
col3$p_val <- p( c( params.data[ col3["item"], c("a1", "a2", "b1",
"b2", "c") ],
examinees.data[ col3["examinee"], c("theta1",
"theta2")]
)
)
If you had provided executable test data I would have tested it, but I
am getting rather bored with creating such for posters who won't
follow the posting guide. If you had just used dput() around those
calls to head() it would have been trivial. As it is, I am not sure if
this will properly run. Could need a different "driving" construction
to get the values of col3 to "feed through" to the row indices. Or
have any number of stoopid errors.
--
David Winsemius
On Mar 1, 2009, at 11:47 AM, Kevski wrote:
I'm completely stumped and seem to be going around for 2 days in the
wrong
circles. Here's what I have in 2 dataframes:
dim(params.data); head(params.data, n=2)
[1] 284 6
item a1 a2 b1 b2 c
1 1 0.6671587 0.9588642 -3.5 -3.437961 0.2
2 2 1.1296298 1.4899307 -3.5 -4.146118 0.2
dim(examinees.data); head(examinees.data, n=2)
[1] 1600 3
examinee theta1 theta2
1 1 -3 -3.133437
2 2 -3 -3.293341
I also have a function, p(), that takes on values for a1, a2, b1,
b2, c,
theta1, and theta2, then outputs a value.
I would like to produce a 3-column array that is 284*1600 = 454400
rows long
for my simulator. Somthing like:
examinee item p
1 1 1 p-value
2 1 2 p-value
...
454399 1600 283 p-value
454400 1600 284 p-value
My brain seems to be stuck in a for-loop loop. I'm sure there is an
elegant
and efficient R way to do this, but I can't seem to find the right
brain
prompts in help pages, forum searches, or my trusty R Book. So, I
appreciate
any guidance you might be able to provide.
Cheers,
Kev-
--
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
