Dear Juan Carlos, > x = c(1,1,3,3,6,7,8,8,9) > table(x) x 1 3 6 7 8 9 2 2 1 1 2 1 > z<-table(x) > z x 1 3 6 7 8 9 2 2 1 1 2 1 > as.vector(z) [1] 2 2 1 1 2 1
Take a look at ?table and ?vector for more information. HTH, Jorge On Mon, Mar 2, 2009 at 4:41 PM, Juancarlos Laguardia <[email protected]>wrote: > Hi, > > I have a problem in which i am having trouble vectorizing a snippet of my > code to avoid a for loop. A basic example of what I'm trying to do is > below. > > #simple example of problem > > x = c(1,1,3,3,6,7,8,8,9) > > # I create a vector that contains the unique values of x > > y = unique(x) > > y = c(1,3,6,7,8,9) > > #### Now I want to create a vector, say z, in which has the same length of > y, but counts how many repetitions occurred for x. > > ## I want > > z = c(2,2,1,1,2,1) > > > ## The only way I've been able to think about this problem is in terms of > a for/while loop to generate z. I'm having trouble thinking on this one. > > If someone could help me out, I would greatly appreciate this. > > Carlos > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
