Why not use the x=T and y=T paramemters and see if :
linearmodel=lm(y~x, x=T, y=T)linearmodel$model
(linearmodel$model)
y x
1 2 1
2 4 2
3 6 3
4 8 4
5 10 5
.... give you useful results. If you want to interpolate or
extrapolate, then search for threads regarding those tasks.
--
David Winsemius
On May 11, 2009, at 11:20 AM, Gerrit Voigt wrote:
Dear List,
Consider the following example
x=c(1,2,3,4,5)
y=c(2,4,6,8,10)
linearmodel=lm(y~x)
To predict a y-value if you know the corresponding x value is very
easy with the command predict.
predict(linearmodel, newdata=(x=1.5))
The other way around, to predict an x-value with a corresponding y-
value, doesn't work unfortunately.
Is there another function that can do that, or do I need to solve
that problem the classical way?
Thanks in advance
Gerrit Voigt
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David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
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and provide commented, minimal, self-contained, reproducible code.
