The 'ties.method' argument to 'rank' is the *third* positional argument to
'rank', so either you need to put it in the third position or you need to
use a named argument.
The fact that the variable you're using to represent ties.method is called
ties.method is irrelevant. That is, this:
rank(x,ties.method)
is equivalent to
rank(x, na.last = ties.method)
which is not what you want.
You need to write
rank(x, ties.method = ties.method)
or (more concise but not as clear):
rank(x, , ties.method)
Hope this helps,
-s
On Wed, May 27, 2009 at 10:11 AM, utkarshsinghal <
[email protected]> wrote:
> I define the following function:
> (Please don't wonder about the use of this function, this is just a
> simplified version of my actual function. And please don't spend your time
> in finding an alternate way of doing the same as the following does not
> exactly represent my function. I am only interested in a good explanation)
>
> > f1 = function(x,ties.method="average")rank(x,ties.method)
> > f1(c(1,1,2,4), ties.method="min")
> [1] 1.5 1.5 3.0 4.0
>
> I don't know why it followed ties.method="average".
> Anyways I randomly tried the following:
>
> > f2 = function(x,ties.method="average")rank(x,ties.method=ties.method)
> > f2(c(1,1,2,4), ties.method="min")
> [1] 1 1 3 4
> Now, it follows the ties.method="min"
>
> I don't see any explanation for this, however, I somehow mugged up that if
> I define it as in "f1", the ties.method in rank function takes its default
> value which is "average" and if I define as in "f2", it takes the value
> which is passed in "f2".
>
> But even all my mugging is wasted when I tested the following:
>
> > h = function(x, a=1)x^a
> > g1 = function(x, a=1)h(x,a)
> > g1(x=5, a=2)
> [1] 25
>
> > g2 = function(x, a=1)h(x,a=a)
> > g2(x=5, a=2)
> [1] 25
>
> Here in both the cases, "h" is taking the value passed through "g1", and
> "g2".
>
> Any comments/hints can be helpful.
>
> Regards
> Utkarsh
>
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