[I neglected to check some details in the previous post]

This one should work better,

library(grid)

x= c(0, 0.5, 1)
y= c(0.5, 1, 0.5)
grid.polygon(x=x, y=y, gp=gpar(fill=NA, col="grey90")) # outer shell

xx <- seq(range(x)[1],range(x)[2], length=100)
dx <- diff(xx) # width of clipped triangles
cols <- colorRampPalette(c("green", "lightgray"))(length(dx))

for(ii in seq_along(xx[-length(xx)])){
grid.clip(x=xx[ii], y=0.5,
width= 1.2*dx[ii], # fudge factor to overlap well
height=1,
just="bottom")
# if(ii%%2)# testing with every other masked
grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(fill=cols[ii], col=cols[ii]))
}





HTH,

baptiste

Kexin Ji wrote:
Hi,

I wonder whether there is a way to generate a polygon (a triangle in my case) with color gradient using grid.polygon() in package grid?

I tried something like

library(grid)
grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(col=NA, fill=colorRampPalette(c("green", "lightgray"),
                                        space="Lab")(200)))

But am only getting a triangle filled with color green, whereas the aim is a triangle of color gradient from green to lightgray.

Can grid.polygon() generate a color gradient, or am I being mistaken?

Best to my knowledge, is it true that R currently doesn't contain any other function that might generate a polygon with color gradient?

Thank you!

Kexin


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Baptiste AuguiƩ

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University of Exeter
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