On 7/10/2009 5:21 AM, e-letter wrote: > I have data like so: > > time datum > 30 12 > 60 24 > 90 37 > 120 41 > 150 8 > > In addition to standard deviation, I want to measure the average of > the differences in data for each time interval, i.e. average of 24-12, > 37-24, 41-37, 8-41. Is there a statistical term for this task? Which > package should I use please?
I don't know a term for it, but you might try something like this: mydf <- data.frame(time = c(30,60,90,120,150), datum = c(12,24,37,41,8)) diff(mydf$datum) [1] 12 13 4 -33 mean(abs(diff(mydf$datum))) [1] 15.5 ?diff > rh...@conference.jabber.org > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Chuck Cleland, Ph.D. NDRI, Inc. (www.ndri.org) 71 West 23rd Street, 8th floor New York, NY 10010 tel: (212) 845-4495 (Tu, Th) tel: (732) 512-0171 (M, W, F) fax: (917) 438-0894 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.