try this,

do.call(rbind, tmp)

baptiste

2009/7/17 Angel Spassov <anspas...@googlemail.com>

> Dear useRs and developeRs,
>
> I am struggling with a simple but not obviously solvable issue. Suppose I
> have the following list of data.frames called 'tmp':
>
> a <- data.frame(a=rnorm(10),b=letters[1:10])
> (tmp <- list(a,a[1:4,],a[1:7,]))
>
> It is known that all data.frames in this list have the same number of
> columns (and this is a good thing). I want to build a bigger data.frame
> consisting of all list-members, e.g. the result should look like:
>
> (res <- rbind(tmp[[1]],tmp[[2]],tmp[[3]]))
>
> The question is how could I do this most efficiently? My real list consist
> of about 700 data.frames, each with with exactly 10 columns and plenty of
> rows. The obvious for-loop solution is rather time consuming and therefore
> I'm looking for something more efficient.
>
> Thank you in advance,
> AS.
>
> ps: 'sapply' should somehow do the trick, doesn't it?
>
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>
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> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 

_____________________________

Baptiste AuguiƩ

School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK

Phone: +44 1392 264187

http://newton.ex.ac.uk/research/emag
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